How do I find the derivative of $ln (ln (2 x))$ $ln(ln(2x))$ ?

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Answer 1 · 2018-05-11T11:29:13

$\frac{d y}{d x} = \frac{1}{x ln (2 x)}$ $dy/dx=1/(xln(2x))$

$y = ln (ln (2 x))$ $y=ln(ln(2x))$

$\frac{d y}{d x} = \frac{d}{d x} [ln (ln (2 x))]$ $dy/dx=d/dx[ln(ln(2x))]$

$\frac{d y}{d x} = \frac{\frac{d}{d x} [ln (2 x)]}{ln (2 x)}$ $dy/dx=(d/dx[ln(2x)])/ln(2x)$

$\frac{d y}{d x} = \frac{(\frac{\frac{d}{d x} [2 x]}{2 x})}{ln (2 x)}$ $dy/dx=(((d/dx[2x])/(2x)))/ln(2x)$

$\frac{d y}{d x} = \frac{(\frac{2}{2 x})}{ln (2 x)}$ $dy/dx=((2/(2x)))/ln(2x)$

$\frac{d y}{d x} = \frac{(\frac{1}{x})}{ln (2 x)}$ $dy/dx=((1/x))/ln(2x)$

$\frac{d y}{d x} = \frac{1}{x ln (2 x)}$ $dy/dx=1/(xln(2x))$

How do I find the derivative of ln(ln(2x))ln(ln(2x))?