Question

If the length of a `24 cm` spring increases to `87 cm` when a `5 kg` weight is hanging from it, what is the spring's constant?

Answer 1

`"77.78 N/m"`

Explanation:

Use this equation

`"F = kx"`

Where

• `"F ="` Force applied
• `"k ="` Spring constant
• `"x ="` Increase in length of spring

`"k" = "F"/"x" = "mg"/"x" = ("5 kg × 9.8 m/s"^2)/"0.87 m – 0.24 m" = "77.78 N/m"`