How do you solve for x in this problem? 4x^2 - 3 = -x?
3 Answers
Explanation:
"rearrange into standard form "color(white)(x)ax^2+bx+c=0
"add "x" to both sides"
rArr4x^2+x-3=0larrcolor(blue)"in standard form"
"factor the quadratic using the a-c method"
"the factors of the product "4xx-3=-12
"which sum to + 1 are + 4 and - 3"
"split the middle term using these factors"
4x^2+4x-3x-3=0larrcolor(blue)"factor by grouping"
color(red)(4x)(x+1)color(red)(-3)(x+1)=0
"take out the "color(blue)"common factor "(x+1)
rArr(x+1)(color(red)(4x-3))=0
"equate each factor to zero and solve for x"
x+1=0rArrx=-1
4x-3=0rArrx=3/4
Use the quadratic formula
Explanation:
First we rearrange;
now we have
and
After subbing everything in we get
the answer
Explanation:
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