How do I find an equation for the tangent line to the graph of #f(x)=(sqrt(x))/(4x-8)# at the point #(3, f(3)#)?
I don't understand what I'm supposed to do with #f(3)# for #y# . Am I supposed to find the derivative of the graph for the slope at the points first then somehow use x and y to find my #y=mx+b# ?
I don't understand what I'm supposed to do with
1 Answer
Equation of tangent line ,
Explanation:
To find the equation of the tangent line we must first find the gradient at the given point, i.e,
So ,
And from the equation of a straight line ,
So the equation of the tangent line becomes