Question

How do you write an equation of a line that passes through (4,-3) and has a slope of -3/4?

Answer 1

`4y+3x=0`

Explanation:

Using the point gradient form: `(y-y_1)=m(x-x_1)`,

your gradient is `-3/4`
your point is `(4,-3)`

Equation:

`(y+3)=-3/4(x-4)`

`4y+12=-3x+12`

`4y+3x=0`