If the length of a 63 cm spring increases to 98 cm when a 15 kg weight is hanging from it, what is the spring's constant?
1 Answer
May 14, 2018
Explanation:
We use Hooke's law, which states that,
where:
F is the force exerted on the spring in newtons
k is the spring constant, usually in newtons per meter
x is the extension of the spring in meters
Here:
F=15 \ "kg"*9.8 \ "m/s"^2=147 \ "N"
x=(98 \ "cm"-63 \ "cm")*(1 \ "m")/(100 \ "cm")=0.35 \ "m"