Question

What are the local extrema, if any, of `f(x)= 4x+6/x`?

Answer 1

At plus or minus Radical three halves

Explanation:

Differentiating we have `f'(x) = 4 - 6/x^2`. We set this equal to 0, as a necessary condition. This gives `4 - 6/x^2=0` so we have `sqrt(3/2)` and `-sqrt(3/2)` as our extrema.