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How do you factor $-8x^2 +32$ ?

1 Answer

May 15, 2018

$-8x^2+32=8[4-x^2]=-8[x^2-4]=8[(x-2)*(x+2)]$

Explanation:

show below

$-8x^2+32=8[4-x^2]=-8[x^2-4]=8[(x-2)*(x+2)]$

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