The force applied against an object moving horizontally on a linear path is described by #F(x)= x^2 + 7 N #. By how much does the object's kinetic energy change as the object moves from # x in [ 2, 5 ]#?

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Answer 1 · 2018-05-15T05:48:37

The change in kinetic energy is #=60J#

The change in kinetic energy is equal to the work done.

#DeltaKE=W=Fxxd#

#W=intF(x)dx=int_2^5(x^2+7)#

#=[x^3/3+7x]_2^5#

#=(125/3+35)-(8/3+14)#

#=60J#