How do you find the slope of #x + y = -3#?

2 Answers
May 15, 2018

See a solution process below:

Explanation:

The standard form of a linear equation is: #color(red)(A)x + color(blue)(B)y = color(green)(C)#

Where, if at all possible, #color(red)(A)#, #color(blue)(B)#, and #color(green)(C)#are integers, and A is non-negative, and, A, B, and C have no common factors other than 1

#color(red)(1)x + color(blue)(1)y = color(green)(-3)#

The slope of an equation in standard form is: #m = -color(red)(A)/color(blue)(B)#

Substituting the values from the equation in the problem gives the slope as:

#m = -color(red)(1)/color(blue)(1) = -1#

May 15, 2018

#"slope" = -1#

Explanation:

Recall equation of a line: #y = mx + c#

Where;

#m -> "slope"#

Given;

#x + y = -3#

Making #y# the subject formula..

#x + y = - 3#

Subract #x# from both sides..

#x - x + y = - 3 - x#

#0 + y = - 3 - x#

#y = - 3 - x#

#y = -x - 3#

#y = -1(x) - 3#

Hence the slope of the equation is #-1#