What is the value of #x# in the equation #(x-2)/3 + 1/6 = 5/6#?

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Answer 1 · 2018-05-17T19:54:06

#x=4#

Let's multiply the first term by #2/2# to achieve a common denominator. Now, we have

#(2(x-2))/6+1/6=5/6#

We can multiply every term by #6# to get

#2(x-2)+1=5#

Suddenly this equation becomes much more easier to solve. We can distribute the #2# to both terms in parenthesis to get

#2x-4+1=5#

Which simplifies to

#2x-3=5#

Adding #3# to both sides, we get

#2x=8#

Lastly, we can divide both sides by #2# to get

#x=4#

Hope this helps!