Question

How do you solve `y=x^2+3`?

Answer 1

As such, you can not 'solve' this

Explanation:

Consider the parent graph of `y=x^2` This is of general shape `uu` and the bottom of the curved part (vertex) ist at the origin `(x,y)->(0,0)`

Now if we add 3 we are effectively 'lifting' the whole thing up by 3. So now the vertex is still on the on the y-axis but at the point `(x,y)->(0,3)` instead of `(0,0)`

Mathematically:

The graph crosses the y-axis at `x=0` so by substitution:

`y=x^2+3 color(white)("dddd")-> color(white)("dddd")y=(0)^2+3 = 3`