Question

What is the equation of the line between `(3,-2)` and `(-23,11)`?

Answer 1

`y=-1/2x-1/2`

Explanation:

The formula for a linear graph is `y=mx+b` . To solve this problem, you have to find the `m`-value first. To do this, use the slope formula:

(`(y_1-y_2)/(x_1-x_2)`)

For this formula you will use the two points that are given; (3, -2) and (-23, 11):

(`(11-(-2))/((-23)-3)` = `-13/26` = `-1/2` →Slope

After finding the slope, you have to find the `b`-value. To do that, you will plug in the new slope and one of the given points:

`y=-1/2x+b`
→ `-2=-1/2(3)+b`
→ `-2=-3/2+b`
→ `+3/2` To both sides
→`-1/2=b`

After finding the `b` and `m`-value, plug them into the form `y=mx+b` and you have your answer:

`y=-1/2x-1/2`