How do you integrate int x /sqrt( 16+x^4 )dx using trigonometric substitution?
1 Answer
May 19, 2018
Use the substitution
Explanation:
Let
I=intx/sqrt(16+x^4)dx
Apply the substitution
I=1/2intd theta
The integral is trivial:
I=1/2theta+C
Reverse the substitution:
I=1/2tan^(-1)(x^2/4)+C