Question

How do you use the discriminant to find the number of real solutions of the equation 3x^2-5x+4=0?

Answer 1

Use the formula

`x=(-(-5)\pmsqrt((-5)^2-(4 xx 3 xx4)))/(2 xx3)`

`x=(5\pmsqrt(25-48))/6`

`x=(5\pmsqrt(-23))/6`

Cannot take the square root of a negative number so no real solutions.