How do you factor #b^2-4b-60#?

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Answer 1 · 2018-05-20T15:04:11

#(b-10)(b+6)#

#b^2-4b-60#

find to numbers that their product is #-60# and their sum is #-4#

which they are -10 and +6

so:

#(b-10)(b+6)#

to check multiply them together and you suppose to get the original equation back

#(b-10)*(b+6)#

#b^2+b6-10b-60#

#b^2-4b-60#

Answer 2 · 2018-05-20T15:07:42

#(b-10)(b+6)#

#"the factors of - 60 which sum to - 4 are - 10 and + 6"#

#rArrb^2-4b-60=(b-10)(b+6)#