How do you factor #b^2-4b-60#?

2 Answers
May 20, 2018

#(b-10)(b+6)#

Explanation:

#b^2-4b-60#

find to numbers that their product is #-60# and their sum is #-4#

which they are -10 and +6

so:

#(b-10)(b+6)#

to check multiply them together and you suppose to get the original equation back

#(b-10)*(b+6)#

#b^2+b6-10b-60#

#b^2-4b-60#

May 20, 2018

#(b-10)(b+6)#

Explanation:

#"the factors of - 60 which sum to - 4 are - 10 and + 6"#

#rArrb^2-4b-60=(b-10)(b+6)#