How do you find the 6 trigonometric functions for -pi/2? Trigonometry Right Triangles Trigonometric Functions of Any Angle 1 Answer VinÃcius Ferraz May 21, 2018 See below Explanation: #sin (-pi/2) = -1# and #cos(-pi/2) = 0# #tan (-pi/2) = (-1)/0 = # undetermined #cot (-pi/2) = 0/(-1) = 0# #sec (-pi/2) = 1/0 = # undetermined #cossec (-pi/2) = 1/(-1) = -1# Answer link Related questions How do you find the trigonometric functions of any angle? What is the reference angle? How do you use the ordered pairs on a unit circle to evaluate a trigonometric function of any angle? What is the reference angle for #140^\circ#? How do you find the value of #cot 300^@#? What is the value of #sin -45^@#? How do you find the trigonometric functions of values that are greater than #360^@#? How do you use the reference angles to find #sin210cos330-tan 135#? How do you know if #sin 30 = sin 150#? How do you show that #(costheta)(sectheta) = 1# if #theta=pi/4#? See all questions in Trigonometric Functions of Any Angle Impact of this question 6379 views around the world You can reuse this answer Creative Commons License