How do you solve #2x+1=8#?

2 Answers
May 24, 2018

See a solution process below:

Explanation:

First, subtract #color(red)(1)# from each side of the equation to isolate the #x# term while keeping the equation balanced:

#2x + 1 - color(red)(1) = 8 - color(red)(1)#

#2x + 0 = 7#

#2x = 7#

Now, divide each side of the equation by #color(red)(2)# to solve for #x# while keeping the equation balanced:

#(2x)/color(red)(2) = 7/color(red)(2)#

#(color(red)(cancel(color(black)(2)))x)/cancel(color(red)(2)) = 7/2#

#x = 7/2#

#x = 7/2#

Explanation:

The first step is to get #x# by itself. You subtract the #1# from both sides

#2x +1-1=8-1#

So now you only have

#2x=7#

You divide both sides by #2# to get #x# by itself.

#(2x)/2=7/2#

and you get your answer!

#x=3.5#