Question

What is the equilibrium constant of `CH_3COOH(aq) + C_2H_5OH(aq) -> CH_3COOC_2H_5 (aq) + H_2O(l)`?

Answer 1

`K_"eq"=(CH_3COOC_2H_5)/((CH_3COOH)(C_2H_5OH))`

Explanation:

`K_"eq"="Products"/"Reactants"`

Reactions always find equilibrium at the least restrictive phase which in this problem, is aq. `H_2O` is then represented as a one because it is in a liquid state. Technically you could put a one in the equation but anything times one is itself so there's no need.