How do you solve -10x^2 + 30x - 20 = 0.?

2 Answers
May 27, 2018

x= 2, 1

Explanation:

given, -10x^2 + 30x -20=0
Multiplying both sides with -1
we get,
10x^2 - 30x +20=0

By Using quadratic formula {x= (-b +- sqrt(b^2-4ac))/(2a)}
we get,

rArr x= (30 +- sqrt(30^2 - 4*10*20))/(2*10)
rArr x = (30 +- 10)/20
rArr x = 40/20 , x = 20/20
Thus we get the value of x as x = 2,1

May 27, 2018

x=2
x=1

Explanation:

Given -

-10x^2+30x-20=0

-10(x^2-3x+2)=0

Dividing both sides by 10 we get

x^2-3x+2=0

x^2-x-2x+2=0

x(x-1)-2(x-1)=0

(x-2)(x-1)=0

x-2=0

x=2

x-1=0

x=1