How do you evaluate sin 5pi/3?

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Answer 1 · 2018-05-27T18:40:41

#(-sqrt3)/2#

Using the unit circle:

#sin((5pi)/3) = (-sqrt3)/2#

Answer 2 · 2018-05-28T02:14:06

#-sqrt3/2#

Use trig table.
#sin ((5pi)/3)) = sin (-pi/3 + (6pi)/3) = sin (- pi/3 + 2pi) = sin (-pi/3) = - sin (pi/3) = - sqrt3/2#