Where does the graph of # y = 3x^2 − 10x − 8# cross the x-axis?
1 Answer
May 28, 2018
Explanation:
#"to find where the graph crosses the x-axis set y = 0"#
#3x^2-10x-8=0#
#"using the a-c method to factor the quadratic"#
#"the factors of the product "3xx-8=-24#
#"which sum to - 10 are - 12 and + 2"#
#"split the middle term using these factors"#
#3x^2-12x+2x-8=0larrcolor(blue)"factor by grouping"#
#color(red)(3x)(x-4)color(red)(+2)(x-4)=0#
#"take out the "color(blue)"common factor "(x-4)#
#(x-4)(color(red)(3x+2))=0#
#"equate each factor to zero and solve for x"#
#x-4=0rArrx=4#
#3x+2=0rArrx=-2/3#
graph{3x^2-10x-8 [-10, 10, -5, 5]}