How do you graph using the intercepts for 2x+6y=0?

1 Answer
May 29, 2018

Refer to explanation below.

Explanation:

2x + 6y = 0

First rearrange the equation.
2x + 6y = 0
6y = 0 - 2x
y = (-2x)/6

Now, substitute x = 0 into the equation to find the intersection with the y-axis.
y=(-(2*0))/6
y=0/6
y=0
Therefore the graph intersects the y-axis at (0, 0)

Now, substitute y = 0 into the equation to find the intersection with the x-axis.
0=(-(2x))/6
6*0=-2x
0/-2=x
Therefore the graph intersects the x-axis at (0, 0)

The gradient of the graph is found by looking at the coefficient of x.
y=(-(2x))/6
y=(-(1x))/3
y=(-1/3)x
Therefore the graph is observed to have a negative gradient with the value of 1/3

graph{2x + 6y = 0 [-10, 10, -5, 5]}