Question

Solve for x where pi <= x <= 2pi ? Tan^2 x + 2 sqrt(3) tan x + 3 = 0

Answer 1

`x=npi+(2pi)/3` where `n in ZZ`

Explanation:

`rarrtan^2x+2sqrt3tanx+3=0`

`rarr(tanx)^2+2*tanx*sqrt3+(sqrt3)^2=0`

`rarr(tanx+sqrt3)^2=0`

`rarrtanx=-sqrt3=tan((2pi)/3)`

`rarrx=npi+(2pi)/3` where `n in ZZ`