Question

How do you use the chain rule to differentiate `y=cos^6x`?

Answer 1

`-6sin(x)cos(x)^5`

Explanation:

first you take the derivative as normal which is
`6*cos(x)^5`
then by the chain rule you take the derivative of the inner function which is cosin in this case and multiply it. The derivative of cos(x) is -sin(x).
`6*cos(x)^5*-sin(x)`

= `-6sin(x)cos(x)^5`