Question

Neon gas has a volume of 2,000ml with an atm of 1.8, however if the pressure decreases to 1.3atm, what is now the volume of the neon gas?

Answer 1

Approximately `2769 \ "mL"~~2.77 \ "L"`.

Explanation:

I'm assuming that there's no change in temperature. Then we can use Boyle's law, which states that,

`Pprop1/V` or `P_1V_1=P_2V_2`

So, we get:

`1.8 \ "atm"*2000 \ "mL"=1.3 \ "atm"*V_2`

`V_2=(1.8color(red)cancelcolor(black)"atm"*2000 \ "mL")/(1.3color(red)cancelcolor(black)"atm")`

`~~2769 \ "mL"`