How do you solve # 5y - 2y = 3y + 2#?

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Answer 1 · 2018-05-31T11:58:02

# 5y-2y=3y+2# so #3y=3y+2# so #0=2# so there are no solutions.

Answer 2 · 2018-05-31T11:58:39

No solution.

#5y-2y=3y+2#

Subtract #2y# from #5y# to get:

#5y-2y=3y+2#
#3y=3y+2#

Move all the terms containing variable #y# to one side of the equation:

#3y-3y=2#

Subtract #3y# from #3y#:

#3y-3y=2#
#0=2#

Since #2!=0#, there would be no solutions for #y#.