Question

How do you solve `16-3q=10`?

Answer 1

`q= 2`

Explanation:

Using Distributive Property..

`16 - 3q = 10`

Subtracting `16` from both sides;

`16 - 3q - 16 = 10 - 16`

`16 - 16 - 3q = 10 - 16`

`0 - 3q = -6`

`-3q = -6`

Dividing both sides by the coefficient of `q;`

`(-3q)/(-3) = (-6)/(-3)`

`(cancel(-3)q)/cancel(-3) = (cancel-6)/(cancel-3)`

`q = 6/3`

`q= 2`

Answer 2

`q=2`

Explanation:

`"isolate "-3q" by subtracting 16 from both sides"`

`cancel(16)cancel(-16)-3q=10-16`

`-3q=-6`

`"divide both sides by "-3`

`(cancel(-3) q)/cancel(-3)=(-6)/(-3)rArrq=2`

`color(blue)"As a check"`

`"left side "=16-(3xx2)=16-6=10=" right side"`