How do you solve #a/(a+3)+a^2/(a+3)=2#?

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Answer 1 · 2018-06-04T11:48:31

#a=-2 or a=3#

#a/(a+3)+a^2/(a+3)#

#:.(a+a^2=2(a+3))/(a+3)#

multiply both sides by #a+3#

#:.a+a^2=2a+6#

#:.a^2+a-2a-6=0#

#:.a^2-a-6=0#

#:.=(a+2)(a-3)#

#:.a=-2 or a=3#