Solve the differential equation : dy/dx +y/x =x²y^6 ?

1 Answer
Jun 4, 2018

#y = root(5)(2/5)x^(-3/5)#

Explanation:

Look for a solution in the form:

#y=cx^n#

then the equation becomes:

#cnx^(n-1) + cx^n/x = c^6x^(6n+2)#

#(cn+c) x^(n-1) = c^6x^(6n+2)#

#n+1 = c^5x^(5n+3)#

As the left hand side is constant, the right hand side must be constant for any #x#, which is possible only if:

#5n+3 = 0#

#n=-3/5#

then:

#c^5 = -3/5+1 = 2/5#

#c= root(5)(2/5)#

and the solution is:

#y = root(5)(2/5)x^(-3/5)#

In fact:

#d/dx( root(5)(2/5)x^(-3/5)) +root(5)(2/5)x^(-3/5)/x = -3/5root(5)(2/5)x^(-8/5) + root(5)(2/5)x^(-8/5)#

#d/dx( root(5)(2/5)x^(-3/5)) +root(5)(2/5)x^(-3/5)/x = (1-3/5) root(5)(2/5)x^(-8/5)#

#d/dx( root(5)(2/5)x^(-3/5)) +root(5)(2/5)x^(-3/5)/x = 2/5 root(5)(2/5)x^(-8/5)#

#d/dx( root(5)(2/5)x^(-3/5)) +root(5)(2/5)x^(-3/5)/x = x^2(root(5)(2/5))^6x^(-18/5)#

#d/dx( root(5)(2/5)x^(-3/5)) +root(5)(2/5)x^(-3/5)/x = x^2(root(5)(2/5)x^(-3/5))^6#