Question

How do you solve for x in `ax+b=cx+d`?

Answer 1

`x=(d-b)/(a-c), a-c!=0`

Explanation:

Isolate the terms with x:

`ax+b=cx+d`

`ax-cx=d-b`

factor out x:

`x(a-c)=d-b`

divide:

`x=(d-b)/(a-c), a-c!=0`