Graph the line with the slop 1/3 and y-intercept -2?

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Answer 1 · 2018-06-06T01:24:30

Please see below.

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The equation of a straight line is:

#y=mx+b# where #m# is the slope and #b# is the #y#-intercept.

Therefore, the equation for this line is:

#y=1/3x-2#

To graph it we can identify two points on the line and connect them together.

#x=0, :. y=-2# this is the #y#-intercept given in the problem.

#x=6, :. y=0# this is the #x#-intercept

Therefore, the two points are:

#(0,-2) and (6,0)#

Locate them on the coordinate system and connect them together.

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