How do you solve #\frac{2}{3} x - 3x + 21= 0#?

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Answer 1 · 2018-06-06T17:47:56

#x=9#

First, subtract #21# from both sides.

#2/3x - 3x = 21#

Second, add like terms. Then you should have

#-7/3x=-21#

Third, multiply both sides by #-3#, leaving you with

#7x=63#

Fourth, divide both sides by #7# and then you will end with

#x =9#

Answer 2 · 2018-06-06T18:04:01

#color(red)(=>x=9)#

#2/3x-3x+21=0#

#=>2/3x-9/3x+21=0#

#=>-7/3x+21=0#

#=>cancel-7/3x=cancel-21#

#=>7x=63#

#color(red)(=>x=9#

~Hope this helps! :)