Question

How do you complete the square for `y=3x^2-24x+10`?

Answer 1

`y = 3(x-4)^2 -38`

Explanation:

Easiest way to complete the square is to use formula for vertex form:
`y = a(x-h)^2 + k`
where `h = frac{-b}{2a}` and `k = \frac{-b^2}{4a} + c`

`a = 3, b =-24, c = 10`
`h= \frac{-(-24)}{2(3)} = 4`
`k = \frac{-(-24)^2}{4(3)} + 16 = -48 + 10 = -38`

Thus the vertex form is `y = 3(x-4)^2 -38`