How do you complete the square for $y=3x^2-24x+10$ ?

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Answer 1 · 2018-06-07T04:58:00

$y = 3(x-4)^2 -38$

Easiest way to complete the square is to use formula for vertex form:
$y = a(x-h)^2 + k$
where $h = frac{-b}{2a}$ and $k = \frac{-b^2}{4a} + c$

$a = 3, b =-24, c = 10$
$h= \frac{-(-24)}{2(3)} = 4$
$k = \frac{-(-24)^2}{4(3)} + 16 = -48 + 10 = -38$

Thus the vertex form is $y = 3(x-4)^2 -38$

How do you complete the square for y=3x^2-24x+10y=3x^2-24x+10?