How do you graph #1 + 2sin(2x - pi)#?

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Answer 1 · 2018-06-07T07:04:49

As detailed.

Standard form of sinusoidal function is #y = A sin (Bx -C) + D#

Given #y = 2 sin (2x - pi) + 1#

#A = 2, B = 2, C = pi, D = 1#

#Amplitude = |A| = 2#

#"Period " = (2pi) / |B| = (2pi)/2 = pi#

#"Phase Shift " = -C / B = pi/2#, #color(red)(pi/2 " to the right"#

#"Vertical Shift " = D = 1#

graph{2 sin(2x -pi) + 1 [-10, 10, -5, 5]}