How do you sketch the graph of #y= cos (2πx- π/2) +1#?

1 Answer
Jun 7, 2018

As below

Explanation:

Standard form #y = A cos (Bx - C) + D#

Given #y = cos (2pix - pi/2) + 1#

#A = 1, B = 2pi, C = pi/2, D = 1#

#Amplitude = |A| = 1#

#"Period " = (2pi) / |B| = (2pi) / (2pi) = 1#

#"Phase Shift " = -C / B = (pi/2) / (2pi) = 1/4#, #color(crimson)(1/4 " to the right"#

#"Vertical Shift " = D = 1#

graph{cos (2pix - pi/2) + 1 [-10, 10, -5, 5]}