Question

How do you differentiate `f(x)=1/(x-3)^2` using the chain rule?

Answer 1

`f'(x)=-2/(x-3)^3`

Explanation:

Writing
`f(x)=(x-3)^(-2)`

then we get after

`(x^n)'=nx^(n-1)`

`f'(x)=-2(x-3)^(-3)`