How do you solve #2x^2+6x=0#?

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Answer 1 · 2018-06-08T18:52:27

#x=-3" or "x=0#

#"factor the quadratic"#

#2x(x+3)=0#

#"equate each factor to zero and solve for x"#

#2x=0rArrx=0#

#x+3=0rArrx=-3#

Answer 2 · 2018-06-08T18:52:53

#x=0, x=-3#

Factor out the GCF:

#2x^2+6x=0#

#2x(x+3)=0#

#2x=0#

#x=0#

#x+3=0#

#x=-3#