How do you find the roots, real and imaginary, of #y= -5x^2 - 24x # using the quadratic formula?

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Answer 1 · 2018-06-09T08:39:58

#;. x= (-b +- b) / (2a) = 0, -b / a = 0, -24/5#

#y = -5x^2 - 24x

#y = ax^2 + bx + c# is the standard form.

#a = -5, b = -24, c = 0#

Since c = 0, discriminator #sqrt(b^2 - 4ac) = +-b#

#;. x= (-b +- b) / (2a) = 0, -b / a = 0, -24/5#

This can be verified by simplifying the equation

#y = -5x (x + 24/5)#