How do you find the roots, real and imaginary, of #y=-2(x+1)^2-(x-3)^2-10 # using the quadratic formula?

Question

960 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2018-06-09T09:10:43

#color(blue)(x = (1 - isqrt62)/3, (1 + i sqrt62) / 3#

#y = -2(x+1)^2 - (x-3)^2 - 10#

#y = -2x^2 - 4x - 2 -x^2 + 6x - 9 - 10#

#y = -3x^2 + 2x - 21#

#a = -3, b = 2, c = =-21#

#x = (-b +- sqrt(b^2 - 4ac)) / (2a)#

#x = (-2 +- sqrt(4 - 252)) / - 6#

#color(blue)(x = (1 - isqrt62)/3, (1 + i sqrt62) / 3#