Question

How do you find the roots, real and imaginary, of `y= -4x^2 + x^2 +6` using the quadratic formula?

Answer 1

`color(indigo)("Roots are " x = -sqrt(3/2) , sqrt(3/2)`

Explanation:

`y = -4x^2 + x^2 + 6`

`y = -3x^2 + 6`

`a = -3, b = 0, c = 6`

`x = (0 +- sqrt(0 +96)) / -8`

`x = sqrt96/-8, sqrt96/8`

`color(indigo)("Roots are " x = -sqrt(3/2) , sqrt(3/2)`