Question

How do you graph `y=1+2cos(1/2x+pi/2)`?

Answer 1

graph{y=1+2cos(.5x + pi/2) [-10, 10, -5, 5]}

Explanation:

Just like graphing a regular function find the vertical stretch factor, horizontal stretch factor, horizontal shift, and vertical shift:
it is shifted up 1 and to the left `pi/2`
it has a vertical stretch actor of 2
it has a horizontal stretch factor of 2
except this is on a cosin function so it looks like this.
graph{y=1+2cos(.5x + pi/2) [-10, 10, -5, 5]}