The force applied against an object moving horizontally on a linear path is described by #F(x)= x^2 + x N #. By how much does the object's kinetic energy change as the object moves from # x in [ 1 , 2 ]#?

1 Answer
Jun 11, 2018

The change in kinetic energy is #=3.83J#

Explanation:

The change in kinetic energy is equal to the work done.

#DeltaKE=W=Fxxd#

#W=int_1^2(x^2+x)dx#

#=[x^3/3+x^2/2]_1^2#

#=(8/3+2)-(1/3+1/2)#

#=14/3-5/6#

#=23/6=3.83J#