How do you solve #-x^2+2x-1 #?

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Answer 1 · 2018-06-11T18:28:53

#x=1# (double answer)

a way of solving it it with sum and multiplication. with an equation like this one in the form #ax^2+bx+c=0# the sum of your answers is

-b/a and the multiplication is c/a.
so in this case:

sum: #-2/-1=2#

multiplication: #-1/-1=1#

So what numbers have sum 2 and multiplication 1?

#1+1=2#

#1*1=1#

1 and 1! so #x=1#