How do you solve #3/(2x-1) - 4/(3x-1) = 1#?

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Answer 1 · 2018-06-12T13:59:49

#x=0 or x=1#

multiply by #(2x-1)(3x-1)#

#3(3x-1)-4(2x-1)=(2x-1)(3x-1)#

#9x-3-8x+4=6x^2-2x-3x+1#

#x+1=6x^2-5x+1#

#6x^2-6x=0#

#6x(x-1)=0#

#x=0 or x=1#