How do you solve the system #14x+5y=31, 2x-3y=-29#?

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Answer 1 · 2018-06-12T17:49:28

#y=9,x=-1#

#(1) 14x+5y=31#
#(2) 2x-3y=-29#

Let's eliminate the y's the isolate the x and solve for x.
To do this, multiply (1) by 3, and (2) by 5.

#(1) 42x+15y=93#
#(2) 10x-15y=-145#

(1)+(2) to eliminate y.

This leaves us with:

#52x=-52#

therefore #x=-1#

Substitute this back into one of the original equation to get:

#-14+5y=31#
Solve for y,
#y=9#