A container with a volume of #8 L# contains a gas with a temperature of #220^o C#. If the temperature of the gas changes to #360 ^o K# without any change in pressure, what must the container's new volume be?

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Answer 1 · 2018-06-13T05:42:13

The new volume is #=5.84L#

Apply Charles' Law

#"Volume"/"Temperature" =" Constant"# at #" constant pressure"#

#V_1/T_1=V_2/T_2#

The initial volume is #V_1=8L#

The initial temperature is #T_1=220^@C+273=493K#

The final temperature is #T_2=360K#

The final volume is

#V_2=T_2/T_1*V_1=360/493*8=5.84L#