How do you solve #x^2 - x - 6 = 0#?
1 Answer
Jun 13, 2018
Explanation:
#"the factors of - 6 which sum to - 1 are - 3 and + 2"#
#(x-3)(x+2)=0#
#"equate each factor to zero and solve for "x#
#x+2=0rArrx=-2#
#x-3=0rArrx=3#
