Question

How can you evaluate `(2)/(2x+1) + (4)/(x-2)`?

Answer 1

Put over a common denominator

Explanation:

I assume you mean "How can I put all of this over one fraction?"

Notice that multiplying by a fraction whose numerator and denominator are the same is multiplying by 1, changing nothing. Multiply each fraction by the other denominator in this fashion:

`2/(2x+1)+4/(x-2)=2/(2x+1)(x-2)/(x-2)+4/(x-2) (2x+1)/(2x+1)`
`=(2(x-2)+4(2x-1))/((2x+1)(x-2))=(10x-8)/((2x+1)(x-2))`