How do you simplify $(16xy^7)/(4xy^3)$ ?

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Answer 1 · 2018-06-14T05:55:46

$4y^4$

Exponential Laws:

$1/a = a^-1$

$1/a^2 = a^-2$

$a/a^2 = a^(1-2) = a^-1$

So now lets simplify:

$(16xy^7)/(4xy^3)$ = $(16cancel(x)y^(7-3))/(4cancel(x))$ -----> simplifying variables first.

$(16cancel(x)y^(7-3))/(4cancel(x))$ = $(16y^4)/4$ = $4y^4$

Hope this helps!

How do you simplify (16xy^7)/(4xy^3)(16xy^7)/(4xy^3)?